72[3(1-n)-2(1+n)]=14

Solution for 72[3(1-n)-2(1+n)]=14 equation:

Simplifying
72[3(1 + -1n) + -2(1 + n)] = 14
72[(1 * 3 + -1n * 3) + -2(1 + n)] = 14
72[(3 + -3n) + -2(1 + n)] = 14
72[3 + -3n + (1 * -2 + n * -2)] = 14
72[3 + -3n + (-2 + -2n)] = 14

Reorder the terms:
72[3 + -2 + -3n + -2n] = 14

Combine like terms: 3 + -2 = 1
72[1 + -3n + -2n] = 14

Combine like terms: -3n + -2n = -5n
72[1 + -5n] = 14
[1 * 72 + -5n * 72] = 14
[72 + -360n] = 14

Solving
72 + -360n = 14

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-72' to each side of the equation.
72 + -72 + -360n = 14 + -72

Combine like terms: 72 + -72 = 0
0 + -360n = 14 + -72
-360n = 14 + -72

Combine like terms: 14 + -72 = -58
-360n = -58

Divide each side by '-360'.
n = 0.1611111111

Simplifying
n = 0.1611111111